(x-2)(y 2x-4)= x-2 ^3 y=x a 345631-(x-2)(y+2x-4)= x-2 ^3 y=x+a

WebAs you have pointed out Putting ( x, y) = ( t, t 2) will give you lim t → 0 2 t 4 2 t 4 = lim t → 0 1 = 1 Using the path ( x, y) = ( t, 0) gives lim t → 0 2 t 2 ⋅ 0 t 4 = lim t → 0 0 = 0 Since you got